
Integer
Multiplication 

Unit 5
> Lesson 6 of 11 
Problem:

Alicia owes $6 to each of 4 friends. How much money does she owe?


Solution: 
The problem above can be solved using
integers.


Owing $6 can be represented by ^{}6. Thus the problem becomes:


(^{}6) (^{+}4)

The parentheses indicate that these integers are being multiplied. In order to solve this problem, we
need to know the rules for multiplication of integers. 
Rule 1: 
The product of a positive integer and a negative integer is a negative integer.

Rule 2: 
The product of two negative integers or two positive integers is a positive integer. 
We can now use Rule 1 to solve the problem above arithmetically:
(^{}6) (^{+}4) = ^{}24. So Alicia owes $24. Let's look at some more examples of multiplying integers
using these rules. 
Example 1:

Find the product of each pair of integers.



Multiplying Integers 
Integers 
Product 
Rule Used 
(^{+}7) (^{+}3) = 
^{+}21 
Rule 2 
(^{+}7) (^{}3) = 
^{}21 
Rule 1 
(^{}7) (^{+}3) = 
^{}21 
Rule 1 
(^{}7) (^{}3) = 
^{+}21 
Rule 2 

Example 2:

Find the product of each pair of integers.



Multiplying Two Integers 
Integers 
Product 
Rule Used 
(^{+}8) (^{+}4) = 
^{+}32 
Rule 2 
(^{+}11) (^{}2) = 
^{}22 
Rule 1 
(^{}14) (^{+}3) = 
^{}42 
Rule 1 
(^{}9) (^{}5) = 
^{+}45 
Rule 2 

In each of the above examples, we multiplied two integers by applying the rules at the top of the page.
We can multiply three integers, two at a time, applying these same rules. Look at the example below. 
Example 3:

Find the product of each set of integers.



Multiplying Three Integers 
Integers 
Product of First Two Integers and the Third 
Product 
(^{+}5) (^{+}3) (^{+}2) = 
(^{+}15) (^{+}2) = 
^{+}30 
(^{+}8) (^{+}2) (^{}5) = 
(^{+}16) (^{}5) = 
^{}80 
(^{}6) (^{+}3) (^{+}4) = 
(^{}18) (^{+}4) = 
^{}72 
(^{}9) (^{}3) (^{+}2) = 
(^{+}27) (^{+}2) = 
^{+}54 
(^{}4) (^{}3) (^{}5) = 
(^{+}12) (^{}5) = 
^{}60 

The
Associative Law of Multiplication
applies to integers. In Example 3 above, we multiplied the product of the first and
second integer by the third integer. We can also solve these problems by multiplying the first
integer by the product of the second and third. We will do this in Example 4 below. 
Example 4:

Find the product of each set of integers.



Multiplying Three Integers 
Integers 
Product of First Integer and the Last Two 
Product 
(^{+}5) (^{+}3) (^{+}2) = 
(^{+}5) (^{+}6) = 
^{+}30 
(^{+}8) (^{+}2) (^{}5) = 
(^{+}8) (^{}10) = 
^{}80 
(^{}6) (^{+}3) (^{+}4) = 
(^{}6) (^{+}12) = 
^{}72 
(^{}9) (^{}3) (^{+}2) = 
(^{}9) (^{}6) = 
^{+}54 
(^{}4) (^{}3) (^{}5) = 
(^{}4) (^{+}15) = 
^{}60 

Summary:

Multiplying two integers with like signs yields a positive product, and multiplying two integers
with unlike signs yields a negative product. We can multiply three integers, two at a time,
applying these same rules.

Exercises
Directions: Read each question below. Click once in an ANSWER BOX and type in your answer; then click ENTER.
After you click ENTER, a message will appear in the RESULTS BOX to indicate whether your answer is correct or incorrect.
To start over, click CLEAR. 
1.

(^{}2) (^{+}7) = ?

2.

(^{}8) (^{}9) = ?

3.

(^{+}9) (^{+}7) = ?

4.

(^{+}16) (^{}3) = ?

5.

(^{+}4) (^{}5) (^{}2) = ?

This lesson is by Gisele Glosser. You can find me on Google.
