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Area of a Triangle Part II Unit 1 > Lesson 4 of 8


Example 1: Find the area of an acute triangle with a base of 15 inches and a height of 4 inches. [IMAGE]
Solution:
  A = · (15 in) · (4 in)
  A = · (60 in2)
  A = 30 in2

Example 2: Find the area of a right triangle with a base of 6 centimeters and a height of 9 centimeters. [IMAGE]
Solution:
  A = · (6 cm) · (9 cm)
  A = · (54 cm2)
  A = 27 cm2

Example 3: Find the area of an obtuse triangle with a base of 5 inches and a height of 8 inches. [IMAGE]
Solution:
  A = · (5 in) · (8 in)
  A = · (40 in2)
  A = 20 in2

Example 4: The area of a triangular-shaped mat is 18 square feet and the base is 3 feet. Find the height. (Note: The triangle in the illustration to the right is NOT drawn to scale.)
Solution: In this example, we are given the area of a triangle and one dimension, and we are asked to work backwards to find the other dimension.
  18 ft2 = · (3 ft) · h   
  Multiplying both sides of the equation by 2, we get:
  36 ft2 = (3 ft) · h
  Dividing both sides of the equation by 3 ft, we get:
  12 ft = h
  Commuting this equation, we get:
  h = 12 ft

Summary: Given the base and the height of a triangle, we can find the area. Given the area and either the base or the height of a triangle, we can find the other dimension. The formula for area of a triangle is: [IMAGE]
 
  or    where b is the base, h is the height



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