Author 
Topic 

effort
Senior Member
USA
38 Posts 
Posted  03/02/2014 : 10:04:21

An object traveling in a straight line has position x(t) at time t. If the initial position is x(0) = 2 and velocity of the object is v(t) = (1 + t), what is the position of the object at time t = 3?
I know that the answer is 6.512. I just don't know how to show that. Would you please show me how to solve this? 


Ultraglide
Advanced Member
Canada
299 Posts 
Posted  03/03/2014 : 16:26:08

Are you sure the antiderivative is correct? 


Ultraglide
Advanced Member
Canada
299 Posts 
Posted  03/04/2014 : 23:40:07

Maybe I should rephrase that. Are you sure the velocity function is correct? 


effort
Senior Member
USA
38 Posts 
Posted  03/05/2014 : 13:07:09

Ultraglide, you are right. It was a typo. It should have been v(t)= (1 + (t)).....only the t should have been squared.
I did figure how to do it. Since the integral of v(t) from 0 to 3= x(3)x(0)=x(3) 2 , then 2 + that same integral = x(3) which gives 6.51153 


Ultraglide
Advanced Member
Canada
299 Posts 
Posted  03/06/2014 : 12:13:03

The two velocity functions you wrote are identical. Is there not another 't' in the function, i.e. v(t)=t(1+t)? 



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