the_hill1962
Advanced Member
USA
1469 Posts 
Posted  08/11/2012 : 10:18:53

You have the correct functions f(x)=x+2 and f(x)=x2 but you have the bounds wrong. The x+2 should be for x2 and the x2 should be for x2 Notice that x=2 gives both f(x) functions a value of zero so that is why both have "or equal to". Probably a better way to state it would be f(x) = x+2 for x>2 x2 for x<2 0 for x=2 Now, I can't explain it the way you were doing it. The way I did it is just graph f(x)=abs(x2) and saw that at x<2, f(x)=x2. At x>2, f(x)=x+2. At x=2, f(x)=0 

