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slice38
Junior Member

USA
3 Posts

Posted - 08/10/2012 :  16:45:01  Show Profile  Reply with Quote
This one is just about to worry me! Can someone help me understand why I can't get this right?

Thanks,
Mike

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the_hill1962
Advanced Member

USA
1468 Posts

Posted - 08/11/2012 :  10:18:53  Show Profile  Reply with Quote
You have the correct functions f(x)=-x+2 and f(x)=x-2 but you have the bounds wrong. The -x+2 should be for x2 and the x-2 should be for x2
Notice that x=2 gives both f(x) functions a value of zero so that is why both have "or equal to".
Probably a better way to state it would be
f(x) =
-x+2 for x>2
x-2 for x<2
0 for x=2
Now, I can't explain it the way you were doing it. The way I did it is just graph f(x)=-abs(x-2) and saw that at x<2, f(x)=x-2. At x>2, f(x)=-x+2. At x=2, f(x)=0
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