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slice38
Junior Member

USA
3 Posts

 Posted - 08/10/2012 :  16:45:01 This one is just about to worry me! Can someone help me understand why I can't get this right?Thanks,Mike

the_hill1962

USA
1468 Posts

 Posted - 08/11/2012 :  10:18:53 You have the correct functions f(x)=-x+2 and f(x)=x-2 but you have the bounds wrong. The -x+2 should be for x2 and the x-2 should be for x2Notice that x=2 gives both f(x) functions a value of zero so that is why both have "or equal to".Probably a better way to state it would bef(x) = -x+2 for x>2x-2 for x<20 for x=2Now, I can't explain it the way you were doing it. The way I did it is just graph f(x)=-abs(x-2) and saw that at x<2, f(x)=x-2. At x>2, f(x)=-x+2. At x=2, f(x)=0
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