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sreesuja
Average Member

India
13 Posts

Posted - 07/10/2012 :  01:25:03  Show Profile  Reply with Quote
USING PROPERTY OF DETERMINANT AND WITHOUT EXPANDING PROVE THAT
[1 1+P 1+P+Q ]
[2 3+2P 1+3P+2Q ] =I
[3 6+3P 1+6P+3Q ]
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royhaas
Moderator

USA
3059 Posts

Posted - 07/10/2012 :  09:18:43  Show Profile  Reply with Quote
Try using row and column operations.
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sreesuja
Average Member

India
13 Posts

Posted - 07/11/2012 :  01:04:05  Show Profile  Reply with Quote
quote:
Originally posted by royhaas

Try using row and column operations.


TRIED BUT NOT GETTING THE ANSWER
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Ultraglide
Advanced Member

Canada
299 Posts

Posted - 07/11/2012 :  15:44:07  Show Profile  Reply with Quote
Show what you've done so far.
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Subhotosh Khan
Advanced Member

USA
9117 Posts

Posted - 07/12/2012 :  14:25:57  Show Profile  Reply with Quote
quote:
Originally posted by sreesuja

USING PROPERTY OF DETERMINANT AND WITHOUT EXPANDING PROVE THAT
[1 1+P 1+P+Q ]
[2 3+2P 1+3P+2Q ] =I
[3 6+3P 1+6P+3Q ]




Multiple posts:

http://mathhelpforum.com/advanced-algebra/200809-determinant.html

http://www.mathisfunforum.com/viewtopic.php?pid=225242

http://www.freemathhelp.com/forum/threads/76401-Algebra
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Ultraglide
Advanced Member

Canada
299 Posts

Posted - 07/12/2012 :  16:58:00  Show Profile  Reply with Quote
I assume you mean one not I.
Here's a hint: use the most complex row to reduce the determinant to three 2x2 determinants. It will work.
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