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Manu
Average Member

Australia
9 Posts

Posted - 04/19/2012 :  02:20:09  Show Profile  Reply with Quote

Is the answer the third option.....
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Subhotosh Khan
Advanced Member

USA
9116 Posts

Posted - 04/24/2012 :  21:35:03  Show Profile  Reply with Quote
quote:
Originally posted by Manu


Is the answer the third option.....




For the third option, the domain changes - so those are not equivalent.

Look at the first option - substitute u = 2*t

then it becomes

x = 5sin(u), y = 6cos(u), z = u : u [0,]

exactly same as given curve
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