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Gregg
Junior Member

USA
3 Posts

 Posted - 03/09/2012 :  13:32:47 Hello;this is a 5th grade math problem. It has fractions in it and also seems like it could be solved with algebra.it takes ben 1/6 of his time to complete task 1. then he needs 2/3 of the remaining time to complete task 2. finally it takes him 4/5 of his remaining time to complete the final task. he completes all tasks with 5 mins remaining. how long did it take ben to complete all tasks?Here's how I've tried to express it so far. I think I want to solve for T. I'm not sure how to go forward from here.(1/6*T) + (2/3*(T-(1/6*T)))+(4/5*(2/3*(T-(1/6*T)))) where T equals Total Time. The solution would then be 5 minutes less than T but I don't know how to simplify and solve the equation.Thank you,Gregg

royhaas
Moderator

USA
3044 Posts

 Posted - 03/09/2012 :  15:27:13 Set it equal to T-5.

Gregg
Junior Member

USA
3 Posts

 Posted - 03/09/2012 :  18:13:48 Thank you for your reply. Do you mean like this?(1/6*T) + (2/3*(T-(1/6*T)))+(4/5*(2/3*(T-(1/6*T)))) = T-5Can I simplify the whole expression, tho? Would I then need to add +5 to both sides in order to get one side to equal T?Based on the information in the problem, can I determine the actual total time or is the final answer just T-5 and T goes unsolved?Thank you,Greggquote:Originally posted by royhaasSet it equal to T-5.

Gregg
Junior Member

USA
3 Posts

 Posted - 03/10/2012 :  14:59:42 Hello;I have an update and more questions.I've been working this problem for the past two days. I found an error with my original expression that caused a problem. The third task should be expressed as (4/5*(T-((1/6*T))+(2/3*(T-1/6T)))). That is, the 4/5 should be multiplied against the sum of the time to complete the first two tasks.So then if the equation were simplified, it looks like this:1/6T + 5/9T + 2/9T = T-5.I can simplify further with LCD by having:3/18T + 10/18T + 4/18T = T-5.Then simplifying further to:17/18T = T-5.At this point I got stuck. I used an Excel spreadsheet to start experimenting with numbers and focused on those divisible by 6.Eventually I found that if T = 90, the solution would work. My problem though is that I still don't know to solve for T in the above expression. How can I get from:17/18T = T - 5 to T=90?????????Thanks,Gregg=4/5*(E1-((1/6*(E1))+(5/9*(E1))))quote:Originally posted by GreggThank you for your reply. Do you mean like this?(1/6*T) + (2/3*(T-(1/6*T)))+(4/5*(2/3*(T-(1/6*T)))) = T-5Can I simplify the whole expression, tho? Would I then need to add +5 to both sides in order to get one side to equal T?Based on the information in the problem, can I determine the actual total time or is the final answer just T-5 and T goes unsolved?Thank you,Greggquote:Originally posted by royhaasSet it equal to T-5.

Ultraglide

279 Posts

 Posted - 03/28/2012 :  00:14:28 To solve the final equation you can remove the ratio by multiplying through by the denominator, in this case 18(17/18)T(18) = T(18)-5(18)which gives 17T = 18T - 90or17T-18T = -90or -T = -90This gives T = 90
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