Math Goodies is a free math help portal for students, teachers, and parents.
|
Interactive Math Goodies Software

testing left nav
Math Forums @ Math Goodies
Home | Profile | Register | Active Topics | Members | Search | FAQ
 All Forums  Homework Help Forums  Algebra  1/29 birth New Topic  Reply to Topic  Printer Friendly
Author  Topic

westworld
Average Member

USA
19 Posts

 Posted - 01/24/2012 :  16:21:21 a mans age at death was 1/29 of the year of his birth. how old will he be in 1982? can anyone help out on this please

Ultraglide

299 Posts

 Posted - 01/25/2012 :  12:55:59 I have a problem with this question. Was he alive or dead in 1982? Anyway, continuing on, his age when he died must divide the year of his birth and result in 29, i.e. if he was 65 and he must have been born in 1885 (65x29=1885). But there are other possibilities:65x29=188566x29=191467x29=194368x29=197269x29=2001Now if you add his age to the year of his birth you get the year of his death65+1885=195066+1914=198067+1943=201068+1972=204069+2001=2070Now it appears that there are three possibilites (I am excluding the fourth case since he would be a child in 1982 and would have to die in 2040. Also in the case of the fifth possibility, he wasn't alive in 1982) with the first two being cases where he was already dead and the third where he was alive.I am sure you can go from there. There is no unique solution to this problem unless he was alive in 1982.
Topic
 New Topic  Reply to Topic  Printer Friendly Jump To: Select Forum New Visitor Forum       Testing Forum Homework Help Forums       Basic Math and Pre-Algebra       Algebra       Geometry and Trigonometry       Pre-Calculus and Calculus       Probability and Statistics       Standardized Test Preparation Help       Miscellaneous Math Topics Educator Forum       Teacher Talk Parent Forum       Parent's Place  -------------------- Home Active Topics Frequently Asked Questions Member Information Search Page
 Math Forums @ Math Goodies © 2000-2004 Snitz Communications