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 Probability and Statistics
 Probability Using General Multiplication Rule
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Average Member

18 Posts

Posted - 10/10/2011 :  03:22:52  Show Profile  Reply with Quote
Would someone please show me how to find P(M1), P(F2), and P(M3) from the problem below

Problem: A company employs six male executives and three female executives. Three executives are randomly selected, one at a time, from the nine executives; the first one selected is sent to China, the second one is sent to New York, and third one is sent to France. Using the general multiplication rule, find the probability that a male is sent to China, a female is sent to New York, and a male is sent to France. Express your answer as a reduced fraction. Hint: Write the probability as P(M1F2M3), then apply the rule.

Here is how I approach the solution:
1. the Sample space S = 9(8)(7) = 504 ways to choose the 3 executives randomly
2. P(M1F2M3) = P(M1)*p(F2|M1)*P(M3|M1F2)
3. But I am not sure how to find P(M1) or P(F2) or P(M3)
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3059 Posts

Posted - 10/12/2011 :  15:18:22  Show Profile  Reply with Quote
Calcuate this in order. How many males are there? What is the probability that a male goes to China? How many females are there? What is the probability that a female goes to NY? How many males are left after one goes to China?
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Average Member

18 Posts

Posted - 10/13/2011 :  01:55:08  Show Profile  Reply with Quote
Thanks for the help.
I think I got it already.
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