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ltruong2
Average Member
USA
18 Posts |
 Posted - 10/10/2011 : 03:22:52
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Would someone please show me how to find P(M1), P(F2), and P(M3) from the problem below
Problem: A company employs six male executives and three female executives. Three executives are randomly selected, one at a time, from the nine executives; the first one selected is sent to China, the second one is sent to New York, and third one is sent to France. Using the general multiplication rule, find the probability that a male is sent to China, a female is sent to New York, and a male is sent to France. Express your answer as a reduced fraction. Hint: Write the probability as P(M1F2M3), then apply the rule.
Here is how I approach the solution:
1. the Sample space S = 9(8)(7) = 504 ways to choose the 3 executives randomly
2. P(M1F2M3) = P(M1)*p(F2|M1)*P(M3|M1F2)
3. But I am not sure how to find P(M1) or P(F2) or P(M3) |
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Probability Using General Multiplication Rule
