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Jack
Junior Member
USA
3 Posts |
 Posted - 05/09/2011 : 14:35:42
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Can anybody HELP me with this problem?
What is the length of diameter of a circle inscribed into a right triangle with the length of hypotenuse c and the sum of the lenghts of legs m. |
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Jack
Junior Member
USA
3 Posts |
Posted - 05/09/2011 : 16:07:42
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I solved this problem by using Theorem that bisectors of angles of right triangle intersect in a center of inscribed circle.
So diameter of this circle D equal : D=m-c |
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Subhotosh Khan
Advanced Member
USA
9114 Posts |
Posted - 05/09/2011 : 17:01:43
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quote:
Originally posted by Jack
Can anybody HELP me with this problem?
What is the length of diameter of a circle inscribed into a right triangle with the length of hypotenuse c and the sum of the lenghts of legs m.
Good work - Jack. |
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TchrWill
Advanced Member
USA
55 Posts |
Posted - 05/13/2011 : 14:13:15
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What is the length of diameter of a circle inscribed into a right triangle with the length of hypotenuse c and the sum of the lenghts of legs m.
Incircle
The internal circle tangent to the three sides and the incenter as center.
The radius of the inscribed circle is r = A/s where A = the area of the triangle and s = the semi-perimeter = (a + b + c)/2, a, b, and c being the three sides.
The radius of the inscribed circle may also be derived from r = ab/(a + b + c).
The radius of the inscribed circle may also be derived from the particular m and n used in deriving a Pythagoraen Triple triangle by r = n(m - n).
If x, y, and z are the points of contact of the incircle with the sides of the triangl e A, B, C, then Cx = Cy = s - c, Bx = Bz = s - b, and Ay = Az = s - a.
The radius of an inscribed circle within a right triangle is equal to r = A/s = s - c where s = (a+b+c)/2 and c = the hypotenuse.
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Edited by - TchrWill on 05/14/2011 11:46:20 |
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Circle inscribed into right triangle
