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kingvg
New Member

USA
2 Posts

 Posted - 03/22/2011 :  20:44:25 (1+ 0.10/12)12t=2

Mrspi

USA
998 Posts

 Posted - 03/23/2011 :  20:48:43 quote:Originally posted by kingvg (1+ 0.10/12)12t=2Since your subject line says "solve EXPONENTIAL equation algebraically," I wonder if you mean that 12t to be an exponent....[1 + (0.10/12)]^(12t) = 2I'd do the arithmetic inside the square brackets first: 1 + (0.10/12) = 1.00833 rounded to 5 decimal places.(1.00833)^(12t) = 2Now, take the log of both sides. You can use either common logs or natural logs. I'll use natural logs (ln):ln (1.00833)^(12t) = ln 2Use the rule of logs which says log a^m = m log a:12t * ln (1.00833) = ln 2t * 12 ln 1.00833 = ln 2Divide both sides of the equation by (12 ln 1.00833):t = (ln 2) / (12 ln 1.00833)Now, it's calculator time....

kingvg
New Member

USA
2 Posts

 Posted - 03/24/2011 :  10:56:26 Yes, 12t is the exponentThanks
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