rijaalu
Junior Member
Taiwan
3 Posts 
Posted  09/04/2010 : 03:23:07

Suppose that for the general population, 1 in 5000 people carries the human immunodeficiency virus (HIV). A test for the presence oh HIV yields either a positive (+) or negative () response. Suppose the test gives the correct answer 99% of the time. What is P[H], the conditional probability that a person test negative given the person does have the HIV virus? What is P[H+], the conditional probability that a random chosen person has the HIV virus given that the person tests positive?
I started working it, but i cannot continue further . Please i will be Glad if someone help me ! Some of my sloution is below.
P(+) = 1/5000 P() = 4999/5000 P(H+) = 1/5000 x 99/100 P(H) = 4999/5000 x 1/100 P(no H+) = 1/5000 x 1/100 P(no H) = 4999/5000 x 99/100


