Subhotosh Khan
Advanced Member
USA
9117 Posts 
Posted  07/15/2009 : 10:52:21

quote: Originally posted by Mimiwold
I the length of a rectangle is 3 more than twice its width. If the perimeter is 22 find the dimensions. How do I do this? Any help appreciated!
First name variables:
Width of rectangle = W
Length of rectangle = L = 2W + 3 (from "...length of a rectangle is 3 more than twice its width") ................ (1)
Perimeter of a rectangle = 2L + 2W = 2(2W + 3) + 2W
perimeter is 22
2(2W + 3) + 2W = 22
Solve for 'W' from above  then solve for 'L' from (1)


