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Haven
Senior Member

USA
28 Posts

 Posted - 09/25/2008 :  08:52:23 The following information was given for the following problem:mx + nx + 16 = 0In the quadratic equation above, m and n are nonzero numbers. If the equation has only one solution, which of the following is equal to m in terms of n?The following answers given were:(a) m = n/2(b) m = n/4(c) m = n/16(d) m = n/16(e) m = n/ 64I need an explanation on how to solve this type of problem. Any assistance would be greatly appreciated.

skeeter

USA
5634 Posts

 Posted - 09/25/2008 :  11:17:53 the general quadratic is ...y = ax+bx+cif y = 0, then x = [-b [sqrt(b-4ac)]/(2a)further, if the quadratic equation has a single solution, then the discriminant, b-4ac, equals 0.in your problem ...a = mb = nc = 16work with that info.

Haven
Senior Member

USA
28 Posts

 Posted - 09/25/2008 :  14:35:01 Thanks again Skeeter. I thought about the general equation but for some reason the "m' and "n" threw me for a curve. Thanks again for all your help.
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