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Haven
Senior Member

USA
28 Posts

Posted - 09/25/2008 :  08:52:23  Show Profile  Reply with Quote
The following information was given for the following problem:
mx + nx + 16 = 0

In the quadratic equation above, m and n are nonzero numbers. If the equation has only one solution, which of the following is equal to m in terms of n?

The following answers given were:

(a) m = n/2

(b) m = n/4

(c) m = n/16

(d) m = n/16

(e) m = n/ 64

I need an explanation on how to solve this type of problem. Any assistance would be greatly appreciated.
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skeeter
Advanced Member

USA
5634 Posts

Posted - 09/25/2008 :  11:17:53  Show Profile  Reply with Quote
the general quadratic is ...

y = ax+bx+c

if y = 0, then x = [-b [sqrt(b-4ac)]/(2a)

further, if the quadratic equation has a single solution, then the discriminant, b-4ac, equals 0.

in your problem ...

a = m
b = n
c = 16

work with that info.


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Haven
Senior Member

USA
28 Posts

Posted - 09/25/2008 :  14:35:01  Show Profile  Reply with Quote
Thanks again Skeeter. I thought about the general equation but for some reason the "m' and "n" threw me for a curve. Thanks again for all your help.
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