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Haven
Senior Member

USA
28 Posts

Posted - 09/19/2008 :  19:59:52  Show Profile  Reply with Quote
I need to know how to find the answer to the following question.

If 5 cards with the letters "A", "B", "C", "D", and "E" are placed in a row so that "A" is never at either end, how many different arrangements are possible?

Any help in regard to describing the math concept this problem involves would also be greatly appreciated.

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skeeter
Advanced Member

USA
5634 Posts

Posted - 09/19/2008 :  20:25:11  Show Profile  Reply with Quote
hope I reasoned it out correctly ... see if this makes sense.

out of 5 cards ...

4 possible choices for one end card, leaving 3 possible choices for the remaining end card. that leaves 3*2*1 choices for the "middle" cards.

how's 4*3*3*2*1 = 72 possible combinations sound?
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Haven
Senior Member

USA
28 Posts

Posted - 09/20/2008 :  16:49:08  Show Profile  Reply with Quote
Thank You Very Much Skeeter.
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