Author 
Topic 

Haven
Senior Member
USA
28 Posts 
Posted  09/19/2008 : 19:59:52

I need to know how to find the answer to the following question.
If 5 cards with the letters "A", "B", "C", "D", and "E" are placed in a row so that "A" is never at either end, how many different arrangements are possible?
Any help in regard to describing the math concept this problem involves would also be greatly appreciated.



skeeter
Advanced Member
USA
5634 Posts 
Posted  09/19/2008 : 20:25:11

hope I reasoned it out correctly ... see if this makes sense.
out of 5 cards ...
4 possible choices for one end card, leaving 3 possible choices for the remaining end card. that leaves 3*2*1 choices for the "middle" cards.
how's 4*3*3*2*1 = 72 possible combinations sound? 


Haven
Senior Member
USA
28 Posts 
Posted  09/20/2008 : 16:49:08

Thank You Very Much Skeeter. 



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