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Haven
Senior Member

USA
28 Posts

 Posted - 09/19/2008 :  19:59:52 I need to know how to find the answer to the following question.If 5 cards with the letters "A", "B", "C", "D", and "E" are placed in a row so that "A" is never at either end, how many different arrangements are possible?Any help in regard to describing the math concept this problem involves would also be greatly appreciated.

skeeter

USA
5634 Posts

 Posted - 09/19/2008 :  20:25:11 hope I reasoned it out correctly ... see if this makes sense.out of 5 cards ...4 possible choices for one end card, leaving 3 possible choices for the remaining end card. that leaves 3*2*1 choices for the "middle" cards.how's 4*3*3*2*1 = 72 possible combinations sound?

Haven
Senior Member

USA
28 Posts

 Posted - 09/20/2008 :  16:49:08 Thank You Very Much Skeeter.
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