Author 
Topic 

Whaty
New Member
USA
1 Posts 
Posted  06/17/2008 : 22:35:09

basically you gotta get all the numbers 1100.
ok so i need to find how to = the numbers 85, 86, 91, 93, 99 or find out if they are possible or not using
the numbers 1, 2, 3, and 4 addition, subtraction, multiplication, division powers, factorials, square root, parentheses
in example if i wanted the number 22
(3!+4^2)/1 = ((3x2x1)+4^2)/1
but i only need 85 86 91 93 and 99 


Subhotosh Khan
Advanced Member
USA
9117 Posts 
Posted  06/18/2008 : 07:00:47

quote: Originally posted by Whaty
basically you gotta get all the numbers 1100.
ok so i need to find how to = the numbers 85, 86, 91, 93, 99 or find out if they are possible or not using
the numbers 1, 2, 3, and 4 addition, subtraction, multiplication, division powers, factorials, square root, parentheses
in example if i wanted the number 22
(3!+4^2)/1 = ((3x2x1)+4^2)/1
but i only need 85 86 91 93 and 99
These are recreational problems  so keep playing around.
I do not think you can prove that a solution does not exist  except for upper bound. 



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