a circular table is pushed into a corner in a rectangular room so that it touches both walls. A point on the edge of the table between the two points of contact is 2 inches from one wall and 9 inches from the othre. What is the radius of the table
a circular table is pushed into a corner in a rectangular room so that it touches both walls. A point on the edge of the table between the two points of contact is 2 inches from one wall and 9 inches from the othre. What is the radius of the table
Please show your work - so that we know where to begin to help you.
1) Draw a sketch of the problem.
2) denote the walls as the x & y axes - write the equation of the circle (table) with radius 'r'.
3) P(2,9) is a point on the circle.
4) solve for 'r' - using (2) and (3)
5) Why did the problem statement include "A point on the edge of the table between the two points of contact ..."?
Got it. Thank you. it results in a quadratic (a-5)(a-17)= and it has to be a = 17
because a = 5 is not feasibleCorrect ... that is where the part "A point on the edge of the table between the two points of contact ..." comes into play
Interactive Math Goodies Software
need help please!!!
Posted - 04/30/2008 : 08:34:25
(85) is not the correct answer
