there is a cube. Two diagonals from the same vertex are drawn, one as face diagonal and the other as space diagonal. Find the measure of angle between the two diagonals. This is how I started . I assumed a 1X1x1 cube. face diagonal came out as sqrt(2) and Space Diagonal came out as sqrt(3). I tried to apply sine rule. There are too many unknowns and hit a brick wall. Appreciate any help
Here is how I solved the problem. Face diagonal will be of size sqrt(2) and space diagonal will be sqrt(3). The angle between the two diagonals will be sine inverse of (1/sqrt3). So the angle is 60 degrees. Mr. Khan, thanks for the response.
Here is how I solved the problem. Face diagonal will be of size sqrt(2) and space diagonal will be sqrt(3). The angle between the two diagonals will be sine inverse of (1/sqrt3)
Interactive Math Goodies Software
Solid Geometry - need help please
Posted - 04/01/2008 : 13:14:29
3) = 35.26438968
