find the classical probability of getting a total of 12 when 5 balanced dice are rolled.
11126 5!/3!=20 11135 5!3!=20 11144 5!3!2!=10 11225 5!(2!2!)=30 11234 5!2!=60 11333 5!(2!3!)=10 12224 5!3!=20 12233 5!(2!2!)=30 22223 5!4!=5 there are 205 outcomes with a total of 12; therefore = 205/7776 There are 6/5 = 7776 possibles outcomes
Interactive Math Goodies Software
can somebody check my work
Posted - 10/24/2007 : 16:52:44
