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adriana
Average Member

USA
8 Posts

Posted - 10/24/2007 :  16:52:44  Show Profile  Reply with Quote
find the classical probability of getting a total of 12 when 5 balanced dice are rolled.

11126 5!/3!=20
11135 5!3!=20
11144 5!3!2!=10
11225 5!(2!2!)=30
11234 5!2!=60
11333 5!(2!3!)=10
12224 5!3!=20
12233 5!(2!2!)=30
22223 5!4!=5
there are 205 outcomes with a total of 12; therefore = 205/7776
There are 6/5 = 7776 possibles outcomes
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royhaas
Moderator

USA
3059 Posts

Posted - 10/24/2007 :  17:13:15  Show Profile  Reply with Quote
All of your totals are 11.
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adriana
Average Member

USA
8 Posts

Posted - 10/24/2007 :  17:46:13  Show Profile  Reply with Quote
quote:
Originally posted by royhaas

All of your totals are 11.



So I need one more?
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pka
Advanced Member

USA
2731 Posts

Posted - 10/24/2007 :  19:09:19  Show Profile  Reply with Quote
Did you even read Prof. Haas' reply?
The whole point is 11126=11 not 12.
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