Author 
Topic 

Ashley8885
Junior Member
USA
5 Posts 
Posted  10/14/2007 : 17:41:07

40x+10y2400 10x+15y2100 5x+15y1500 x0, y0 Minimize the objective function c=6x+8y
FIND THE X AND Y INTERCEPT OF EACH EQUATION.



Ashley8885
Junior Member
USA
5 Posts 
Posted  10/14/2007 : 20:24:19

No I posted this because I need help. 


Mrspi
Advanced Member
USA
998 Posts 
Posted  10/14/2007 : 22:15:13

quote: Originally posted by Ashley8885
40x+10y2400 10x+15y2100 5x+15y1500 x0, y0 Minimize the objective function c=6x+8y
FIND THE X AND Y INTERCEPT OF EACH EQUATION.
I'll help you with ONE of your constraints:
40x + 10y >= 2400
Divide both sides by 10:
4x + y >= 240
Consider the EQUATION 4x + y = 240
To find the xintercept, substitute 0 for y:
4x + 0 = 240 4x = 240 x = 60 The xintercept is at (60, 0).
To find the yintercept for 4x + y = 240, substitute 0 for x:
4(0) + y = 240 y = 240
The yintercept for 4x + y = 240 is (0, 240)
Now...you can do the same for each of the other constraints.



sahsjing
Advanced Member
USA
2399 Posts 
Posted  10/15/2007 : 17:51:58

quote: Originally posted by Ashley8885
40x+10y2400 10x+15y2100 5x+15y1500 x0, y0 Minimize the objective function c=6x+8y
FIND THE X AND Y INTERCEPT OF EACH EQUATION.
If you use a graphing calculator, you can easily see that the minimum c occurs at x = 30, y = 120. Can you tell why? 
Edited by  sahsjing on 10/15/2007 17:54:52 



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