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Ashley8885
Junior Member

USA
5 Posts

 Posted - 10/14/2007 :  17:41:07 40x+10y240010x+15y21005x+15y1500x0, y0Minimize the objective function c=6x+8yFIND THE X AND Y INTERCEPT OF EACH EQUATION.

Ashley8885
Junior Member

USA
5 Posts

 Posted - 10/14/2007 :  20:24:19 No I posted this because I need help.

Mrspi

USA
998 Posts

 Posted - 10/14/2007 :  22:15:13 quote:Originally posted by Ashley888540x+10y240010x+15y21005x+15y1500x0, y0Minimize the objective function c=6x+8yFIND THE X AND Y INTERCEPT OF EACH EQUATION.I'll help you with ONE of your constraints:40x + 10y >= 2400Divide both sides by 10:4x + y >= 240Consider the EQUATION 4x + y = 240To find the x-intercept, substitute 0 for y:4x + 0 = 2404x = 240x = 60The x-intercept is at (60, 0).To find the y-intercept for 4x + y = 240, substitute 0 for x:4(0) + y = 240y = 240The y-intercept for 4x + y = 240 is (0, 240)Now...you can do the same for each of the other constraints.

sahsjing

USA
2399 Posts

 Posted - 10/15/2007 :  17:51:58 quote:Originally posted by Ashley888540x+10y240010x+15y21005x+15y1500x0, y0Minimize the objective function c=6x+8yFIND THE X AND Y INTERCEPT OF EACH EQUATION.If you use a graphing calculator, you can easily see that the minimum c occurs at x = 30, y = 120. Can you tell why? Edited by - sahsjing on 10/15/2007 17:54:52
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