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Ashley8885
Junior Member

USA
5 Posts

Posted - 10/14/2007 :  17:41:07  Show Profile
40x+10y2400
10x+15y2100
5x+15y1500
x0, y0
Minimize the objective function c=6x+8y

FIND THE X AND Y INTERCEPT OF EACH EQUATION.


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Ashley8885
Junior Member

USA
5 Posts

Posted - 10/14/2007 :  20:24:19  Show Profile
No I posted this because I need help.
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Mrspi
Advanced Member

USA
998 Posts

Posted - 10/14/2007 :  22:15:13  Show Profile
quote:
Originally posted by Ashley8885

40x+10y2400
10x+15y2100
5x+15y1500
x0, y0
Minimize the objective function c=6x+8y

FIND THE X AND Y INTERCEPT OF EACH EQUATION.






I'll help you with ONE of your constraints:

40x + 10y >= 2400

Divide both sides by 10:

4x + y >= 240

Consider the EQUATION 4x + y = 240

To find the x-intercept, substitute 0 for y:

4x + 0 = 240
4x = 240
x = 60
The x-intercept is at (60, 0).

To find the y-intercept for 4x + y = 240, substitute 0 for x:

4(0) + y = 240
y = 240

The y-intercept for 4x + y = 240 is (0, 240)

Now...you can do the same for each of the other constraints.


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sahsjing
Advanced Member

USA
2399 Posts

Posted - 10/15/2007 :  17:51:58  Show Profile
quote:
Originally posted by Ashley8885

40x+10y2400
10x+15y2100
5x+15y1500
x0, y0
Minimize the objective function c=6x+8y

FIND THE X AND Y INTERCEPT OF EACH EQUATION.





If you use a graphing calculator, you can easily see that the minimum c occurs at x = 30, y = 120. Can you tell why?

Edited by - sahsjing on 10/15/2007 17:54:52
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