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Pre-Calculus and Calculus

help please....

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nerro_101
Junior Member

Canada
4 Posts

Posted - 10/11/2007 : 08:37:23

Can anyone help me? I've been stuck with this problem for 5 days now. A piece of wire 50 cm long is cut into two pieces AP and PB as shown below. Piece Ap is bent to form a square, while piece PB is bent into a circle. How do I express the total area enclosed by the two figures as a function of x?
(remake of the image below)

-----------x-------------------50-x
.___________________.________________.
point a------------point p----------point b

Thank you.

Edited by - nerro_101 on 10/11/2007 11:49:43

Subhotosh Khan
Advanced Member

USA
9114 Posts

Posted - 10/11/2007 : 09:28:29

quote:
Originally posted by nerro_101

Can anyone help me? I've been stuck with this problem for 5 days now. A piece of wire 50 cm long is cut into two pieces AP and PB as shown below. Piece Ap is bent to form a square, while piece PB is bent into a circle. How do I express the total area enclosed by the two figures as a function of x?
(remake of the image below)

-----------x-------------------50-x
.___________________.________________.
point a------------point p----------point b
Thank you.

Perimeter of a square with side 'L' = 4*L = x

So each side of square = x/4

Area of square = L² = x²/16

Do similar computation for circle and then add the areas up.

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