A row of beads consists of 10 red beads and 5 blue beads. How do I compute the total number of possible arrangements of the beads that have no two blue beads adjacent?
The ten red beads create eleven positions into which one can put the blue beads: _R_R_R_R_R_R_R_R_R_R_ Therefore, there is a combination of eleven places taken five at a time to place the blue beads.
Interactive Math Goodies Software
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Posted - 10/01/2007 : 20:47:21
