Author 
Topic 

dauerbach
Average Member
USA
13 Posts 
Posted  09/20/2007 : 19:19:03

Here is the problem, that I do not really understand.: A Company is decreasing by 10 % the amount of tuna sold in cylindrical cans. The cans will have the same height but a smaller diameter to minimize the impact on consumer when they see the smaller can. By what % should the diameter be decreased to accomodate the change? 


skeeter
Advanced Member
USA
5634 Posts 
Posted  09/20/2007 : 20:44:22

old volume ... V = rh
new volume ... .9V = (kr)h where k is a reduction factor for the radius.
divide new volume by old volume ...
.9V = (kr)h  V = rh
.9 = k
k = (.9) = approx .95
the new radius will be 95% of the length of the old radius, a 5% reduction ... so, the diameter will also decrease by 5% since diameter length varies directly with the radius length. 


jfg4707
Average Member
USA
19 Posts 
Posted  10/13/2007 : 22:06:43

David,
There is a typo. Your (1  D/d) should be (1  d/D). 



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