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dauerbach
Average Member

USA
13 Posts

 Posted - 09/20/2007 :  19:19:03 Here is the problem, that I do not really understand.: A Company is decreasing by 10 % the amount of tuna sold in cylindrical cans. The cans will have the same height but a smaller diameter to minimize the impact on consumer when they see the smaller can. By what % should the diameter be decreased to accomodate the change?

skeeter

USA
5634 Posts

 Posted - 09/20/2007 :  20:44:22 old volume ... V = rhnew volume ... .9V = (kr)h where k is a reduction factor for the radius.divide new volume by old volume ....9V = (kr)h----------------- V = rh.9 = kk = (.9) = approx .95the new radius will be 95% of the length of the old radius, a 5% reduction ... so, the diameter will also decrease by 5% since diameter length varies directly with the radius length.

jfg4707
Average Member

USA
19 Posts

 Posted - 10/13/2007 :  22:06:43 David,There is a typo. Your (1 - D/d) should be (1 - d/D).
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