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Pre-Calculus and Calculus

Calculus - Integration

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Francneto
Junior Member

Angola
3 Posts

Posted - 09/13/2007 : 08:15:01

Could you help me to solve the following problem:

Obtain the reduction formula for INT (cos^n[x]dx)

This is what I have tried:

Using integration by parts:

u = cos^(n-1)(x) du = -n cos^(n-1)(x)sin(x) dx

dv = cos(x)dx v = sin(x)

cos^n(x) dx = sin(x)cos^(n-1)(x) + integral
cos^(n-1)(x)sin^2(x) dx

That's all I could do! I don't know if it is right can you help to do the rest (i.e. obtain the reduction formul)?