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 Calculus - Integration
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Francneto
Junior Member

Angola
3 Posts

Posted - 09/13/2007 :  08:15:01  Show Profile
Could you help me to solve the following problem:

Obtain the reduction formula for INT (cos^n[x]dx)

This is what I have tried:

Using integration by parts:

u = cos^(n-1)(x) du = -n cos^(n-1)(x)sin(x) dx

dv = cos(x)dx v = sin(x)

cos^n(x) dx = sin(x)cos^(n-1)(x) + integral
cos^(n-1)(x)sin^2(x) dx

That's all I could do! I don't know if it is right can you help to do the rest (i.e. obtain the reduction formul)?
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tkhunny
Advanced Member

USA
1001 Posts

Posted - 09/13/2007 :  09:08:16  Show Profile
Hint: Remember that sin(x) + cos(x) = 1
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