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skeeter
Advanced Member
USA
5634 Posts |
Posted - 09/13/2007 : 13:39:30
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f(x) = arctan(x), centered at c = 1 ...
P3(x) = f(1) + f'(1)(x-1) + f"(1)(x-1)2/2 + f'''(x)(x-1)3/6 + R3(x)
R3(x) = f4(z)(x - 1)4/24
f(x) = arctan(x) ... f(1) = /4 f'(x) = 1/(1 + x2) ... f'(1) = 1/2 f''(x) = -2x/(1 + x2)2 ... f''(1) = -1/2 f'''(x) = (6x2 - 2)/(1 + x2)3 ... f'''(1) = 1/2 |
Edited by - skeeter on 09/13/2007 13:40:35 |
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