I'm trying to find the limit of ((2x-9) + 3)/x as x approaches 0. I know that with the original equation if x = 3 then it is 0/0. I tried using the reciprical trick and simplified it down to x/(((2x+9)+3), but that still leaves me without a limit. Is there something I am missing?
No, I made a mistake. Instead of x appraches 0 it should be as x approaches 3. I tested it with an x value of 3 and it gave me 0/0. Sorry about the confusion
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Posted - 09/11/2007 : 22:16:40
(2x-9) + 3)/x as x approaches 0. I know that with the original equation if x = 3 then it is 0/0. I tried using the reciprical trick and simplified it down to x/((
