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dauerbach
Average Member

USA
13 Posts

 Posted - 08/27/2007 :  20:17:06 My back to school review is in progress, and I am blocking.For the function f(x) =x^2 - 4/(x + 3)^2State the domain: Every real number except -3Find the x intercept: Totally blockingFind the y Intercept: +4/9, -4/9Are the two I did correct? What is the x intercept?

tkhunny

USA
1001 Posts

 Posted - 08/27/2007 :  22:59:33 y-intercept: x = 0 and solve for y. Where does the graph hit the y-axis?0^2 - 4/(0+3)^2 = 0 - 4/3^2 = -4/9x-intercept: y = 0 and solve for x. Where does the graph hit the x-axis?0 = x^2 - 4/(x+3)^2 = (x + 2/(x+3))(x - 2/(x+3))Can you find values that work?Domain: Good.No Range?

dauerbach
Average Member

USA
13 Posts

 Posted - 08/29/2007 :  08:57:28 Honestly, I am not sure. I got -4/9 and it just seemed it should be plus or minus. Obviously not.

tkhunny

USA
1001 Posts

 Posted - 08/29/2007 :  10:17:23 quote:Originally posted by dauerbachHonestly, I am not sure. I got -4/9 and it just seemed it should be plus or minus. Obviously not.It is a common error. consider the following...x = 4 has only one solution. x = 4x = -4 has only one solution. x = -4x = 4 has two solutions. x = 2 and x = -2How many solutions has:x = 4 ?How many solutions has:x = -4 ?
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