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[quote][i]Originally posted by jpw00blue[/i] [br]Can this be b and m as well as b and m ? Give what each equation must be to eliminate the term containing x. mx  ny = z bx  ny = r AND Solve for x and y. ax+by = r ax+ cy = s Can it be both x= bscr/a(bc) or x= crbx/acab y= sr/cb or y= rs/bc [/quote]
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T O P I C R E V I E W
jpw00blue
Posted  03/29/2012 : 20:12:48
Can this be b and m as well as b and m ?
Give what each equation must be to eliminate the term containing x.
mx  ny = z
bx  ny = r
AND
Solve for x and y.
ax+by = r
ax+ cy = s
Can it be both x= bscr/a(bc) or x= crbx/acab
y= sr/cb or y= rs/bc
1 L A T E S T R E P L I E S (Newest First)
royhaas
Posted  03/30/2012 : 07:56:11
Multiply numerator and denominator by 1 so that you see that both forms are equivalent.
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