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| T O P I C R E V I E W |
| Zubaida |
Posted - 03/07/2012 : 06:00:43
Hello,
Can please answer my questions regarding the following problem?
A homeowner wishes to insulate her attic with fiberglass insulations to conserve energy. The insulation comes in 40-cm wide rolls that are cut to fit between rafters in the attic. If the roof is 6 m from peak to eave and the attic space is 2 m high at the peak, hoe long does each of the pieces of installation need to be? Round to the nearest tenth.
The solution:
To know how long is the the floor of the attic, we apply the Pythagorean theorem (c = a + b). We substitute, 6 = a + 2.
a= 36 - 4
a= 32
a=  32
a= 5.65685424949
a= 5.7m
Is this is the length of each of the pieces of installation? or should I multiply by two to get the true length (the length of the attic floor)?
The insulation comes in 40-cm wide rolls. Is this information is useless. If not? How can I benefit from?
Thank you, |
| 6 L A T E S T R E P L I E S (Newest First) |
| TchrWill |
Posted - 03/16/2012 : 14:37:36
Thank you TchrWill and the_hill1962 for your explanation.
But why TchrWill said that the length of each piece lying between the roof rafters is 12m. Does he mean that 12 is the result of rounding 11.3 to the nearest tenth? Why not 11m?
Is this because the insulations will not cover all the space if the result is 11m?
Assuming the "6m from peak to eave" is the half-width of the roof surface, the length of each piece of attic floor insulation is sqrt(6^2 - 2^2)2 = sqrt(32)2 = 8sqrt(2)m = 11.3m.
The length of each piece lying between the roof rafters is 12m.
....................B
..................*l
..............*....l
..........*........l
......*............l
._*____________l
A...................C
AB = 6m
BC = 2m
AC = 11.3m
As pointed out, insulation is normally installed between the attic floor rafters. Since it was not specifically stated, and the length of the roof surface was given, the length of both applications was given.
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| the_hill1962 |
Posted - 03/15/2012 : 13:44:45
I wondered the same think myself. I do think that is what he meant (11.3 can't be rounded to 11 in this case because it would make a gap----true, not much of one but I suppose it is important for insulation to be snug since there would be a space where cold or hot air can draft in and out).
About the "40cm" information. That is just how wide it is to fit between the rafters. The length is what needed to be calculated. Using 12m assures that you will have enough. You don't want to be short! Say that you buy just enough using the 11.3m figure. Well, as you cut each length, suppose that you weren't exactly at 11.3m each and you made them a little bit more (just to make sure it is fitting in without leaving gaps and not having to stretch it)-----all that extra adds up and your last piece would be short.
It is better to have extra left.
quote:
Originally posted by Zubaida
Thank you TchrWill and the_hill1962 for your explanation.
But why TchrWill said that the length of each piece lying between the roof rafters is 12m. Does he mean that 12 is the result of rounding 11.3 to the nearest tenth? Why not 11m?
Is this because the insulations will not cover all the space if the result is 11m?
Thank you,
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| Zubaida |
Posted - 03/07/2012 : 16:10:27
Thank you TchrWill and the_hill1962 for your explanation.
But why TchrWill said that the length of each piece lying between the roof rafters is 12m. Does he mean that 12 is the result of rounding 11.3 to the nearest tenth? Why not 11m?
Is this because the insulations will not cover all the space if the result is 11m?
Thank you,
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| the_hill1962 |
Posted - 03/07/2012 : 15:45:45
Insulation is put on the floor of the attic since you don't want the heating and cooling loss stopped there. You don't want the heat and cold energy to be heating and cooling the attic space.
Each piece of insulation would be 232. That is 2162 which is 82. It says to round to the nearest tenth so that would be 11.3m.
quote:
Originally posted by Zubaida
Hello,
I have another question please,
Where will the homeowner put insulations?
If she will put them on the roof, I think there is no need to use the Pythagorean theorem. We multiply 6 by 2 = 12m. Right?
If she will put insulations on the floor, then we should use the Pythagorean theorem to know how long each piece should be (as we solved previously)
Thank you,
Zubaida
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| Zubaida |
Posted - 03/07/2012 : 14:02:53
Hello,
I have another question please,
Where will the homeowner put insulations?
If she will put them on the roof, I think there is no need to use the Pythagorean theorem. We multiply 6 by 2 = 12m. Right?
If she will put insulations on the floor, then we should use the Pythagorean theorem to know how long each piece should be (as we solved previously)
Thank you,
Zubaida
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| TchrWill |
Posted - 03/07/2012 : 10:14:54
A homeowner wishes to insulate her attic with fiberglass insulation to conserve energy. The insulation comes in 40-cm wide rolls that are cut to fit between rafters in the attic. If the roof is 6 m from peak to eave and the attic space is 2 m high at the peak, how long does each of the pieces of installation need to be? Round to the nearest tenth.
Assuming the "6m from peak to eave" is the half-width of the roof surface, the length of each piece of attic floor insulation is sqrt(6^2 - 2^2)2 = sqrt(32)2 = 8sqrt(2)m = 11.3m.
The length of each piece lying between the roof rafters is 12m.
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