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T O P I C R E V I E W
Mimiwold	Posted - 07/14/2009 : 21:02:05 I the length of a rectangle is 3 more than twice its width. If the perimeter is 22 find the dimensions. How do I do this? Any help appreciated!
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Subhotosh Khan	Posted - 07/15/2009 : 10:52:21 quote: Originally posted by Mimiwold I the length of a rectangle is 3 more than twice its width. If the perimeter is 22 find the dimensions. How do I do this? Any help appreciated! First name variables: Width of rectangle = W Length of rectangle = L = 2W + 3 (from "...length of a rectangle is 3 more than twice its width") ................ (1) Perimeter of a rectangle = 2L + 2W = 2(2W + 3) + 2W perimeter is 22 2(2W + 3) + 2W = 22 Solve for 'W' from above - then solve for 'L' from (1)