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T O P I C    R E V I E W
Heather Posted - 10/23/2007 : 19:37:51
I can't figure out this identity, I was wondering if someone could help me with it...

sin-tancos-cot=tan^6
2   L A T E S T    R E P L I E S    (Newest First)
Heather Posted - 10/23/2007 : 20:16:45
Thank you sooo much!! it was like a big DUH when i saw it! haha thanks again!
skeeter Posted - 10/23/2007 : 19:49:14
(sinx - tanx)/(cosx - cotx) =

[sinx(1 - secx)]/[cosx(1 - cscx)] =

(sinx)/(cosx)*(1 - secx)/(1 - cscx) =

tanx * (-tanx)/(-cotx) =

tanx * tanx * tanx =

tan6x

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