Posted - 05/03/2013 : 10:49:44 I have to find the exact value of some inverse trigonometric funstions. I have the answers but don't know how to get the answers. If you will show me how to do one of the problems, I'm sure I can use that as an example to figure out the other 5 problems.

The exact value of the trig function tan((1/2)Arccos (5/13)) is (2/3) but I don't know how to get this answer. Will someone show me how to get this answer?

3 L A T E S T R E P L I E S (Newest First)

effort

Posted - 05/06/2013 : 08:16:47 Here is my work: (1-(5/13)) / (12/13)

which using = (8/13)/(12/13) and using same change flip gives 2/3

the_hill1962

Posted - 05/03/2013 : 18:00:36 Quick response, someguy! I was looking up the half-angle identity and started to work it out. Before I had finished, I logged back in to start a reply in and saw that you already have it all typed out!

someguy

Posted - 05/03/2013 : 12:11:14 Hi Effort,

You are looking for tan(/2) where =arccos(5/13).

Using the half-angle identities for the tangent function is useful here.

tan(/2) = sin()/(1+cos()) = (1-cos())/sin()

Since arcos(5/13) is an angle between 0 and 90 degrees, we can just draw a right triangle, call one of the angles that is less than 90 degrees , and then label the lengths of the adjacent side and hypotenuse as 5 and 13 (so that cos=5/13). The Pythagorean theorem can be used to find the length of the third side. Use this triangle with the identity tan(/2) = sin()/(1+cos()) to find the value of tan(/2).