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T O P I C    R E V I E W
sreesuja Posted - 07/10/2012 : 01:25:03
USING PROPERTY OF DETERMINANT AND WITHOUT EXPANDING PROVE THAT
[1 1+P 1+P+Q ]
[2 3+2P 1+3P+2Q ] =I
[3 6+3P 1+6P+3Q ]
5   L A T E S T    R E P L I E S    (Newest First)
Ultraglide Posted - 07/12/2012 : 16:58:00
I assume you mean one not I.
Here's a hint: use the most complex row to reduce the determinant to three 2x2 determinants. It will work.
Subhotosh Khan Posted - 07/12/2012 : 14:25:57
quote:
Originally posted by sreesuja

USING PROPERTY OF DETERMINANT AND WITHOUT EXPANDING PROVE THAT
[1 1+P 1+P+Q ]
[2 3+2P 1+3P+2Q ] =I
[3 6+3P 1+6P+3Q ]




Multiple posts:

http://mathhelpforum.com/advanced-algebra/200809-determinant.html

http://www.mathisfunforum.com/viewtopic.php?pid=225242

http://www.freemathhelp.com/forum/threads/76401-Algebra
Ultraglide Posted - 07/11/2012 : 15:44:07
Show what you've done so far.
sreesuja Posted - 07/11/2012 : 01:04:05
quote:
Originally posted by royhaas

Try using row and column operations.


TRIED BUT NOT GETTING THE ANSWER
royhaas Posted - 07/10/2012 : 09:18:43
Try using row and column operations.

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