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| cadillacdeville |
Posted - 11/12/2011 : 22:37:09
This is a two part question, I have figured out the first part, but the second part I do not understand. Please help!
First part: You are planning to draw 2 cards (playing cards) at random without replacement. My goal is to pull out a 4 on the first draw and a heart in the second draw and a heart in the second draw.
Second part: Now suppose there is a roll of quarters with one special quarter somewhere in the roll. As the roll of quarters gets bigger, your probability decrease. How many quarters would you need for the probability of selecting the special quarter to be the same as the probability of a pulling out a 4 on the first draw and a heart in the second draw without replacement?
Please help with problem
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| 1 L A T E S T R E P L I E S (Newest First) |
| royhaas |
Posted - 11/13/2011 : 14:34:04
If N is the number of quarters you need, then the probability of selecting a specific quarter in one draw is 1/N. What answer did you get for the first part of the problem? |
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