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T O P I C R E V I E W
jenzy569	Posted - 10/26/2011 : 18:24:44 In testing a new drug, researchers found that 10% of all patients using it will have a mild side effect. A random sample of 14 patients using the drug is selected. Find the probability that: (A) exactly two will have this mild side effect (B) at least three will have this mild side effect. N = 14 (14 patients) X = 2 (exactly 2 will have this mild side effect) P = 0.10 (prob. of all patients using it will have a mild side effect; success) Q = 0.90 (1 - p = 1 - 0.10 = 0.9) (A) = 14!/(14-2)!2! (0.10)�(0.90)14-2^2 = 141312!/12!21(0.10)�(0.90)12^2 = 1413/2*1(0.01)(0.28) = 182/2(0.01)(0.28) = 91(0.01)(0.28) = 0.25 or 25% But I'm not sure how to do part B.....please help!!
1 L A T E S T R E P L I E S (Newest First)
royhaas	Posted - 10/27/2011 : 08:59:01 "At least three" is the complement of "No more than two".