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| T O P I C R E V I E W |
| kingvg |
Posted - 03/22/2011 : 20:44:25
(1+ 0.10/12)12t=2 |
| 2 L A T E S T R E P L I E S (Newest First) |
| kingvg |
Posted - 03/24/2011 : 10:56:26
Yes, 12t is the exponent
Thanks |
| Mrspi |
Posted - 03/23/2011 : 20:48:43
quote:
Originally posted by kingvg
(1+ 0.10/12)12t=2
Since your subject line says "solve EXPONENTIAL equation algebraically," I wonder if you mean that 12t to be an exponent....
[1 + (0.10/12)]^(12t) = 2
I'd do the arithmetic inside the square brackets first: 1 + (0.10/12) = 1.00833 rounded to 5 decimal places.
(1.00833)^(12t) = 2
Now, take the log of both sides. You can use either common logs or natural logs. I'll use natural logs (ln):
ln (1.00833)^(12t) = ln 2
Use the rule of logs which says log a^m = m log a:
12t * ln (1.00833) = ln 2
t * 12 ln 1.00833 = ln 2
Divide both sides of the equation by (12 ln 1.00833):
t = (ln 2) / (12 ln 1.00833)
Now, it's calculator time....
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