|
|
|
Note: You must be registered in order to post a reply. To register, click here. Registration is FREE!
|
| T O P I C R E V I E W |
| nirvanaguy |
Posted - 01/29/2011 : 22:06:04 Hi guys, I really need to understand this as soon as possible so I don't get screwed and left behind in the lectures..
I have2 problems:
z(t)=[e^(-t)*u(t)] * [e^(-t)*u(t)]
I got the answer 1 but for some reason I don't think that's right.. I know that when you analyze it graphically z=0 for t<0 and for t>0 i had my bounds go from 0 to infinity of e^-(t)dt
2nd) [t*e^(-t)*u(t)]*[2*u(t+.5)-2*u(t-.5)]
For this one for my boundaries for when 0<t<1 i used 0 to t and for t>1 I used t-1 to t as my boundaries since thats the width of the unit pulse. however, i'm know thats not right because i graphed them and the area comes out all funky. I think it's wrong because it has somtehing to do with the .5 shifts on both sides instead of just the shift of 1 to the right..
If someone could help out that would be amazing and I will honestly pay you if you'd like |
| 1 L A T E S T R E P L I E S (Newest First) |
| Ultraglide |
Posted - 02/11/2011 : 17:27:22 I am sure you will find all kinds of material on the net. I did. |
|
|
| Math Forums @ Math Goodies |
© 2000-2004 Snitz Communications |
 |
|
|