testing header
Math Goodies is a free math help portal for students, teachers, and parents.
Free Math
Newsletter
 
 
Interactive Math Goodies Software

Buy Math Goodies Software
testing left nav
Math Forums @ Math Goodies
Math Forums @ Math Goodies
Home | Profile | Register | Active Topics | Members | Search | FAQ
 All Forums
 Homework Help Forums
 Pre-Calculus and Calculus
 Geometric & arithmetic sequences... precalc help

Note: You must be registered in order to post a reply.
To register, click here. Registration is FREE!

Screensize:
UserName:
Password:
Format Mode:
Format: BoldItalicizedUnderlineStrikethrough Align LeftCenteredAlign Right Horizontal Rule Insert HyperlinkInsert EmailInsert Image Insert CodeInsert QuoteInsert List Insert Special Characters Insert Smilie
   
Message:
* HTML is OFF
* Forum Code is ON

Math Symbols
Squared [squared] Cubed [cubed] Square Root [sqrt] Cube Root [cbrt] Pi [pi]
Alpha [alpha] Beta [beta] Gamma [gamma] Theta [theta] Angle [angle]
Degrees [degrees] Times [times] Divide [divide] Less Than or Equal To [less-than] Greater Than or Equal To [greater-than]
Plus Minus [plus-minus] Integral [integral] Sum [sum] Sub 1 [sub-1] Sub 2 [sub-2]
Element Of [element-of] Union [union] Intersect [intersect] Subset [subset] Empty Set [empty-set]

  Check here to subscribe to this topic.
 
   

T O P I C    R E V I E W
happysharlee Posted - 01/03/2011 : 19:25:50
Suppose that a, b, and c are three consecutive terms in a geometric sequence. Show that 1/(a+b) , 1/(2b) , and 1/(c+b) are three consecutive terms in an arithmetic sequence.

I have no clue how to approach this question! It's from my textbook, so i know all relevant equations/formulas. Please help me out, my teacher is very strict.


EDIT:
I have a second question:

Let b denote a positive constant. Find the sum of the first n terms in the sequence

1/(1+b) , 1/(1-b) , 1/(1-b) , ...

I get that the denominators must form some kind of arithmetic sequence, but I can't for the life of me figure out what the common difference could be... please help!!
1   L A T E S T    R E P L I E S    (Newest First)
Dr.Steve Posted - 01/04/2011 : 19:22:40
Since the sequence is geometric there is a common ratio r. Then b=ar and c= ar. See if you can take it from there.

Math Forums @ Math Goodies © 2000-2004 Snitz Communications Go To Top Of Page
This page was generated in 0.04 seconds. Snitz Forums 2000
testing footer
About Us | Contact Us | Advertise with Us | Facebook | Blog | Recommend This Page




Copyright © 1998-2014 Mrs. Glosser's Math Goodies. All Rights Reserved.

A Hotchalk/Glam Partner Site - Last Modified 21 Oct 2014