|T O P I C R E V I E W
||Posted - 09/26/2009 : 16:35:28
From the decimal form of 1/13 we pick 99 consecutive digits and treat it as a 99 digit number. Can this number be divisible by 3?
|2 L A T E S T R E P L I E S (Newest First)
||Posted - 09/28/2009 : 10:01:06
That was a clever deduction.
||Posted - 09/27/2009 : 01:40:09
1/13 = .0769230769230769230...
So, the repeating part is 769230 which is the multiple of 3.
Now calculate 99/6 which has the remainder of 3. But none of the three consecutive digits is divisible by 3. Therefore, this number cannot be divisible by 3.