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 T O P I C    R E V I E W Mimiwold Posted - 07/14/2009 : 21:02:05 Ithe length of a rectangle is 3 more than twice its width. If the perimeter is 22 find the dimensions. How do I do this? Any help appreciated! 1   L A T E S T    R E P L I E S    (Newest First) Subhotosh Khan Posted - 07/15/2009 : 10:52:21 quote:Originally posted by MimiwoldIthe length of a rectangle is 3 more than twice its width. If the perimeter is 22 find the dimensions. How do I do this? Any help appreciated!First name variables:Width of rectangle = WLength of rectangle = L = 2W + 3 (from "...length of a rectangle is 3 more than twice its width") ................ (1)Perimeter of a rectangle = 2L + 2W = 2(2W + 3) + 2Wperimeter is 22 2(2W + 3) + 2W = 22Solve for 'W' from above - then solve for 'L' from (1)

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