|T O P I C R E V I E W
||Posted - 11/13/2008 : 07:41:13
Average age of A & B is 24 years and average of B, C & D is 22
years. The sum of the ages A, B, C & D is
a)90 years b) 96 years c)114 years d)data inadequate
|6 L A T E S T R E P L I E S (Newest First)
||Posted - 11/14/2008 : 15:00:03
||Posted - 11/14/2008 : 12:49:44
I was thinking that "insufficient data" is the correct response.
The ONLY data given is two equations:
1. (A+B)/2 = 24
2. (B+C+D)/3 = 22
This means that [3(A+B) + 2(B+C+D)]/6 = 46.
That is 3A+5B+5C+2D=276, nothing more.
||Posted - 11/13/2008 : 18:15:47
the correct response to the problem is - insufficient data.
||Posted - 11/13/2008 : 18:04:02
I made an assumption based upon my understanding of the word "average" and the information given. If my assumption was incorrect, then I stand corrected and kindly give a better explanation.
||Posted - 11/13/2008 : 12:53:54
How do you know B is 24 when you substituted it into B+C+D?
||Posted - 11/13/2008 : 11:37:28
To solve this problem you must have an understanding of what an average is and know how to use the average formula.
To solve this problem:
The first step is to find the value of A or B. The problem tells you that the average of A + B equals 24; by using the average formula this means that A + B divided by 2 equals 24, or multiplying both sides by 2 gives you A + B equals 48. the average value of A or B equals 24.
The second step is to substitute 24 into the second average problem of (B) + C + D = 22; this means that 24 + C + D divided by 3 equals 22, or multiplying both sides by 3 gives 24 + C + D = 66. Subtracting 24 from each side now gives the following C + D = 42
The third step is to take the values of A + B which equals 48, and C + D which equals 42 and add them together; 48 + 42 = 90
I hope this explanation was of some help to you.