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 T O P I C    R E V I E W raghu Posted - 04/30/2008 : 08:34:25 a circular table is pushed into a corner in a rectangular room so that it touches both walls. A point on the edge of the table between the two points of contact is 2 inches from one wall and 9 inches from the othre. What is the radius of the table 7   L A T E S T    R E P L I E S    (Newest First) Subhotosh Khan Posted - 05/01/2008 : 08:49:10 quote:Originally posted by raghuGot it. Thank you. it results in a quadratic (a-5)(a-17)= and it has to be a = 17 because a = 5 is not feasibleCorrect ... that is where the part "A point on the edge of the table between the two points of contact ..." comes into play. Thanks for your help. raghu Posted - 05/01/2008 : 07:40:49 Got it. Thank you. it results in a quadratic (a-5)(a-12)= and it has to be a = 17 because a = 5 is not feasible. Thanks for your help. Subhotosh Khan Posted - 04/30/2008 : 20:50:56 quote:Originally posted by raghuBut, How? sqrt(85) <> 17<<<< because (85) is not the correct answer raghu Posted - 04/30/2008 : 15:00:21 But, How? sqrt(85) <> 17 Subhotosh Khan Posted - 04/30/2008 : 13:26:30 17" is the correct answer. raghu Posted - 04/30/2008 : 10:44:02 This is a problem that appeared in Georgia tech math competition. The answer suggested is 17 inches. I got sqrt(85) as the answer, Subhotosh Khan Posted - 04/30/2008 : 09:17:24 quote:Originally posted by raghua circular table is pushed into a corner in a rectangular room so that it touches both walls. A point on the edge of the table between the two points of contact is 2 inches from one wall and 9 inches from the othre. What is the radius of the tablePlease show your work - so that we know where to begin to help you.1) Draw a sketch of the problem.2) denote the walls as the x & y axes - write the equation of the circle (table) with radius 'r'.3) P(2,9) is a point on the circle.4) solve for 'r' - using (2) and (3)5) Why did the problem statement include "A point on the edge of the table between the two points of contact ..."?

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