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[quote][i]Originally posted by skeeter[/i] [br](sin[squared]x  tan[squared]x)/(cos[squared]x  cot[squared]x) = [sin[squared]x(1  sec[squared]x)]/[cos[squared]x(1  csc[squared]x)] = (sin[squared]x)/(cos[squared]x)*(1  sec[squared]x)/(1  csc[squared]x) = tan[squared]x * (tan[squared]x)/(cot[squared]x) = tan[squared]x * tan[squared]x * tan[squared]x = tan[sup]6[/sup]x [/quote]
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T O P I C R E V I E W
Heather
Posted  10/23/2007 : 19:37:51
I can't figure out this identity, I was wondering if someone could help me with it...
sin
tan
cos
cot
=tan^6
2 L A T E S T R E P L I E S (Newest First)
Heather
Posted  10/23/2007 : 20:16:45
Thank you sooo much!! it was like a big DUH when i saw it! haha thanks again!
skeeter
Posted  10/23/2007 : 19:49:14
(sin
x  tan
x)/(cos
x  cot
x) =
[sin
x(1  sec
x)]/[cos
x(1  csc
x)] =
(sin
x)/(cos
x)*(1  sec
x)/(1  csc
x) =
tan
x * (tan
x)/(cot
x) =
tan
x * tan
x * tan
x =
tan
^{6}
x
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