testing header
Math Goodies is a free math help portal for students, teachers, and parents.
Free Math
Interactive Math Goodies Software

Buy Math Goodies Software
testing left nav
Math Forums @ Math Goodies
Math Forums @ Math Goodies
Home | Profile | Active Topics | Members | Search | FAQ
 All Forums
 Homework Help Forums
 Standardized Test Preparation Help
 Properties of Numbers

Note: You must be registered in order to post a reply.

Format Mode:
Format: BoldItalicizedUnderlineStrikethrough Align LeftCenteredAlign Right Horizontal Rule Insert HyperlinkInsert EmailInsert Image Insert CodeInsert QuoteInsert List Insert Special Characters Insert Smilie
* Forum Code is ON

Math Symbols
Squared [squared] Cubed [cubed] Square Root [sqrt] Cube Root [cbrt] Pi [pi]
Alpha [alpha] Beta [beta] Gamma [gamma] Theta [theta] Angle [angle]
Degrees [degrees] Times [times] Divide [divide] Less Than or Equal To [less-than] Greater Than or Equal To [greater-than]
Plus Minus [plus-minus] Integral [integral] Sum [sum] Sub 1 [sub-1] Sub 2 [sub-2]
Element Of [element-of] Union [union] Intersect [intersect] Subset [subset] Empty Set [empty-set]

  Check here to subscribe to this topic.

T O P I C    R E V I E W
Joe Komagawa Posted - 12/01/2013 : 00:51:27
GMAT-the official guide, #169
If N is a positive integer and N(N) is divisible by 72, then the largest positive integer that must divide N is ?
A) 6, B) 12, C) 24, D) 36, E) 48. Answer is B) 12.
Text* Since N(N) is divisible by 72, N(N)= 72k for some positive integer k." My first thought was to set up 72=n(n)k. But this is wrong. It should be n(n)= 72k. Can you explain?

text: " Since n(n) = 72k then 72k is a perfect square. since 72k =2(2)(2)(3)(3)k then k= 2m(m) for some positive integer M in order for 72k to be a perfect square." I don't follow the idea that k=2m(m).
text: n(n)= 72k==2(2)(2)(3)(3)(2m(m)," so it follows on to the conclusion of a set of integers that MUST divide N are 1,2,3,4,6,12.

I don't see that 6, and 12 are part of this answer set, though since I was stumped earlier, this last puzzle might be obvious.

Math Forums @ Math Goodies © 2000-2004 Snitz Communications Go To Top Of Page
This page was generated in 0.03 seconds. Snitz Forums 2000
testing footer
About Us | Contact Us | Advertise with Us | Facebook | Blog | Recommend This Page

Copyright © 1998-2014 Mrs. Glosser's Math Goodies. All Rights Reserved.

A Hotchalk/Glam Partner Site - Last Modified 18 Dec 2014