Math Goodies is a free math help portal for students, teachers, and parents.
|
Interactive Math Goodies Software

testing left nav
 Math Forums @ Math Goodies Home | Profile | Active Topics | Members | Search | FAQ
 All Forums  Homework Help Forums  Pre-Calculus and Calculus  derivatives of trig

Note: You must be registered in order to post a reply.

Screensize:
Format Mode:
Format:

Message:
* HTML is OFF
* Forum Code is ON

 Math Symbols

Check here to subscribe to this topic.

 T O P I C    R E V I E W effort Posted - 10/17/2013 : 00:25:13 Find the derivative of sec(x).my work: (d/dx)sec(x)=sec(x)tan (x)(2x)My question is why is it that there should be only one 2x. According to the chain rule, I suppose to take the derivative of the inside function. Well, there are two x, so why do I not have to write 2x twice. i don't understand.Also how do you know which is the interior and exterior functions when finding trig derivatives? For example: find dy/dx of y = 4sin(3x) 1   L A T E S T    R E P L I E S    (Newest First) Ultraglide Posted - 10/18/2013 : 17:24:09 When differentiating sec(x), you get sec(x)tan(x). Note that the arguements are both the same. When you apply the chain rule you apply it to the arguement of the secant (i.e. the orginal function), so you only do it once. When you start applying the chain rule, you start with the outer part and work your way 'inside'. In the example you used the sine is the outer and the 3x is the inner.

 Math Forums @ Math Goodies © 2000-2004 Snitz Communications