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 T O P I C    R E V I E W TchrWill Posted - 07/08/2013 : 15:44:09 The digits of a 5 digit number ABCDE have the following relationships:1--The first two digits are the square of the third digit.2--The fourth and fifth digits are the sum of the second and third digits.3--The third digit is twice the second digit.4--The fifth digit is one half the second digit and one third the first digit.5--The sum of the five digits is 21.6--What is the 5 digit number? 2   L A T E S T    R E P L I E S    (Newest First) TchrWill Posted - 07/29/2013 : 13:59:33 quote:Originally posted by someguyProperties 1 and 3 tell you how to start forming the number in question.Properties 1 and 3 say AB is C^2 and C=2*B. We also know C is an integer between 0 and 9.00 (0 is 2*0)01 (1 is not 2*1)04 (2 is not 2*4)09 (3 is not 2*9)16 (4 is not 2*6)25 (5 is not 2*5)36 (6 is not 2*6)49 (7 is not 2*9)64 (8 is 2*4)81 (9 is not 2*1)ABC is either 000 or 648Having the 5 digits sum to 21 rules out 000.The number is 648DE.The second and third digits sum to 12.The number is 64812Note that property 4 was not used, but is satisfied.Nice approach someguy. I have concluded that I tend to take a longer algebraic path. But, that is what makes recreational math interesting.From the given inforamtion:1--10A + B = C^22--10D + E = B + C3--C = 2B4--E = B/2 = A/35--Since 10A + B is a square, the only 2 digit numbers possible are 16, 25, 36, 49, 64, and 81.6--This makes the ABC possibilities 164, 255, 366, 497, 648 and 819.7--Only 648 satisfies the C = 2B requirement and therefore ABC = 648.8--WIth E = B/2 or A/3, E muat be 2 for 648D2.9--Since 10D + E = B + C, 10D + 2 = 4 + 8 making D = 1.10--Thus, the number we seek is 64,812 without using given fact #5.11--Checking: 6+4+8+1+2 = 21.Alternatively1--10A + B = C^22--10D + E = B + C3--C = 2B4--E = B/2 = A/35--A + B + C + D + E = 216--3E + 2E + 4E + (B + C - E)/10 + E = 217--3E + 2E + 4E + 2E/10 + 4E/10 - E/10 + E = 218--Times 10, 30E + 20E + 40E + 2E + 4E - E + 10E = 2109--Collecting, 105E = 210 making E = 2.10--B = 2E making B = 411--A = 3E making A = 6.12--With AB = 64, C = 8.13--Therefore, D = 21 - 6 - 4 - 8 - 2 = 1 for 64,812 someguy Posted - 07/28/2013 : 13:43:23 Properties 1 and 3 tell you how to start forming the number in question.Properties 1 and 3 say AB is C^2 and C=2*B. We also know C is an integer between 0 and 9.00 (0 is 2*0)01 (1 is not 2*1)04 (2 is not 2*4)09 (3 is not 2*9)16 (4 is not 2*6)25 (5 is not 2*5)36 (6 is not 2*6)49 (7 is not 2*9)64 (8 is 2*4)81 (9 is not 2*1)ABC is either 000 or 648Having the 5 digits sum to 21 rules out 000.The number is 648DE.The second and third digits sum to 12.The number is 64812Note that property 4 was not used, but is satisfied.

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