T O P I C R E V I E W 
effort 
Posted  05/16/2013 : 13:50:32 Given cos= 7/9 and tan < 0, find 2
The answer in the book shows (562) / 81 but that is not what I got. My answer is (82)/ 9 Am I just completely wrong or is the solution in the book? Any help is appreciated. 
2 L A T E S T R E P L I E S (Newest First) 
the_hill1962 
Posted  05/17/2013 : 08:48:10 In your Solution1, sin 2 is not equal to (42)/9 That is what sin is equal to. So, since sin=(42)/9 and sin 2 = 2sincos, you get what you have done in the Solution2.

effort 
Posted  05/16/2013 : 19:16:58 Okay, here is my work. I have worked it twice. I have two answers. I don't understand why i can't solve it like the first solution.
Solution 1 Using the pythagorean thm, I found the third side side to be 42. So now, sin 2 = (42)/9 so sin = (82)/9
Solution 2 But if i use the sum formula for sin. I have sin( x + x) which equals sinxcosx + cosxsinx which equals (2)((42)/9)(7/9) which equals what the books has for the solution (562)/9
So i don't understand why I can't solve it like my top???? 

