|
|
|
Note: You must be registered in order to post a reply.
To register, click here. Registration is FREE!
|
| T O P I C R E V I E W |
| slice38 |
Posted - 08/10/2012 : 16:45:01
This one is just about to worry me! Can someone help me understand why I can't get this right?
Thanks,
Mike
 |
| 1 L A T E S T R E P L I E S (Newest First) |
| the_hill1962 |
Posted - 08/11/2012 : 10:18:53
You have the correct functions f(x)=-x+2 and f(x)=x-2 but you have the bounds wrong. The -x+2 should be for x 2 and the x-2 should be for x 2
Notice that x=2 gives both f(x) functions a value of zero so that is why both have "or equal to".
Probably a better way to state it would be
f(x) =
-x+2 for x>2
x-2 for x<2
0 for x=2
Now, I can't explain it the way you were doing it. The way I did it is just graph f(x)=-abs(x-2) and saw that at x<2, f(x)=x-2. At x>2, f(x)=-x+2. At x=2, f(x)=0 |
|
|
| Math Forums @ Math Goodies |
© 2000-2004 Snitz Communications |
 |
|
|
Interactive Math Goodies Software
