| T O P I C R E V I E W |
| sreesuja |
Posted - 07/10/2012 : 01:25:03 USING PROPERTY OF DETERMINANT AND WITHOUT EXPANDING PROVE THAT [1 1+P 1+P+Q ] [2 3+2P 1+3P+2Q ] =I [3 6+3P 1+6P+3Q ]
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| 5 L A T E S T R E P L I E S (Newest First) |
| Ultraglide |
Posted - 07/12/2012 : 16:58:00 I assume you mean one not I. Here's a hint: use the most complex row to reduce the determinant to three 2x2 determinants. It will work. |
| Subhotosh Khan |
Posted - 07/12/2012 : 14:25:57 quote: Originally posted by sreesuja
USING PROPERTY OF DETERMINANT AND WITHOUT EXPANDING PROVE THAT [1 1+P 1+P+Q ] [2 3+2P 1+3P+2Q ] =I [3 6+3P 1+6P+3Q ]
Multiple posts:
http://mathhelpforum.com/advanced-algebra/200809-determinant.html
http://www.mathisfunforum.com/viewtopic.php?pid=225242
http://www.freemathhelp.com/forum/threads/76401-Algebra |
| Ultraglide |
Posted - 07/11/2012 : 15:44:07 Show what you've done so far. |
| sreesuja |
Posted - 07/11/2012 : 01:04:05 quote: Originally posted by royhaas
Try using row and column operations.
TRIED BUT NOT GETTING THE ANSWER |
| royhaas |
Posted - 07/10/2012 : 09:18:43 Try using row and column operations. |