**T O P I C R E V I E W** |

**Katy** |
Posted - 09/26/2009 : 16:35:28 From the decimal form of 1/13 we pick 99 consecutive digits and treat it as a 99 digit number. Can this number be divisible by 3? |

**2 L A T E S T R E P L I E S (Newest First)** |

**Subhotosh Khan** |
Posted - 09/28/2009 : 10:01:06 That was a clever deduction. |

**sahsjing** |
Posted - 09/27/2009 : 01:40:09 1/13 = .0769230769230769230... So, the repeating part is 769230 which is the multiple of 3. Now calculate 99/6 which has the remainder of 3. But none of the three consecutive digits is divisible by 3. Therefore, this number cannot be divisible by 3. |